The vertices of ∆abc are a(2, 8), b(16, 2), and c(6, 2). the perimeter of ∆abc is , and its area is square units.

The vertices of ∆ABC are A(2, 8), B(16, 2), and C(6, 2). The perimeter of ∆ABC is  30  units, and its area is  2  square units.

Perimeter is 32.4 unts

Area is 30.1 square units.  

Step-by-step explanation:

Given the vertices of ∆ABC are A(2, 8), B(16, 2), and C(6, 2). we have to find the area and perimeter of triangle ABC.

By distance formula,

Perimeter=AB+BC+AC=15.2+7.2+10=32.4 units

Now, we find the area of triangle

By Heron's formula

Area is 30.1 square units.      

step-by-step explanation:

the true ones are a b and d

the answer would be d.

step-by-step explanation:

move all variables to the left side and all constants to the right side

(x−3)^2+(y−1)^2=16

this is the form of a circle. use this form to determine the center and radius of the circle.

( x − h ) 2 + ( y − k ) 2 = r 2

match the values in this circle to those of the standard form. the variable   r   represents the radius of the circle,   h   represents the x-offset from the origin, and   k   represents the y-offset from origin.

r = 4

h = 3

k = 1

the center of the circle is found at   ( h , k ) .

center:   ( 3 , 1 )

these values represent the important values for graphing and analyzing a circle.

center:   ( 3 , 1 ).

radius:   4