When finding the margin of error for the mean of a normally distributed population from a sample, what is the critical probability, assuming a confidence level of 58%?
a. 0.21
b. 0.42
c. 0.58
d. 0.79

Answer – A.  0.21

EXPLANATION

Given,
The population has a normal distribution
Confidence level, Cl = 58%
Cl = 58/100
Cl = 0.58

Critical Probability, Pc is unknown

We know that 1 – Cl = 2(Pc)
Therefore, 1 – 0.58 = 2(Pc)
2(Pc) = 0.42

Divide both sides of the equation by 2
2(Pc)/2 = 0.42/2
Pc = 0.21

Therefore, assuming a confidence level of 58% when finding the margin of error for the mean of a normally distributed population from a sample, the
critical probability is 0.21

Its 79%. Critical prob = the alpha (1 subrtracted from confidencen interval over 100) divided by 2 then subtracted from 1. This is 79%