Alice plays the following game with bob. first, alice randomly chooses a set of 4 cards out of a 52-card deck, memorizes them, and places them back into the deck. (any set of 4 cards is equally likely.) then, bob randomly chooses 8 cards out of the same deck. (any set of 8 cards is equally likely.)
what is the probability that all 4 cards alice chose were also among the 8 cards chosen by bob?

Choosing 8 cards out of a deck of 52 cards and that the order is not important can be determined through the equation,
                                    52C8 = 752538150
If the four cards initially picked by Alice should be present, we take them as 1 whole set. Such that picking 8 cards would only give us 5 (1 set of 4 cards and 4 other cards). That is,
                                  52C5 = 2598960
The probability is solved by dividing the latter by the former, giving us the answer of 56/16215 which is also equal to 0.00345

Then just do it (lol)