the length of a rectangle is 59 inches greater than twice the width. if the diagonal is 2 inches more than the length, find the dimensions of the rectangle.

So.. hmm notice the picture here

we know the length is 59 more than twice the width,
twice the width, 2 * w, or 2w
59 more than that
2w + 59

we also know that, whatever that is, the diagonal of it is,
2 more inches than that, or
(2w + 59) + 2

now.. use the pythagorean theorem


you'd end up with a quadratic, after simplifying, solve for "w"