In a billiards game, peter hits a ball that is 20 in. from the wall the ball travels 34 inches until it hits the wall and bounces to a position that is 16 inches from the wall what is the distance x the ball traveled after it bounces off the wall to get to the ending position

27.2 inches

Step-by-step explanation:

Given :

Refer the attached figure

ΔABC AND ΔEDC are right angled triangle at B and D respectively

So we will use trigonometric ratios :

IN ΔABC  perpendicular = AB=20 inches  and hypotenuse = AC=34 inches

IN ΔEDC perpendicular = ED=16 inches  and hypotenuse = EC=x inches

Since ∠ACB = ∠ECD

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Thus distance X the ball traveled after it bounces off the wall to get to the ending position =27.2 inches

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step-by-step explanation: