Va stands for vertical asymptote and ha stands for horizontal asymptote. i have no clue what that means and i don't know what a hole is either

A VA is a vertical line that an equation will approach but never touch. 

To solve for a VA take the denominator and set it equal to zero because a number divided by zero is undefined. (You can check this on a calculator by taking 2/0, you will get error)

For this equation set x+4=0, solve for x, you will get x=-4 as your VA

A HA is similar since it is a horizontal line that an equation approaches but never touches.

To solve for an HA I learned a rule called the BB rule or B00bie Butt rule. I know it is silly but it is easy to remember. Here are three examples:
(1) 2x^2/x^2
(2) 2x/x^2
(3)2x^2/x
To solve you look at the degree of the equation.
(1) This has the same degree on top and bottom (x^2) so you take the leading coefficient (2/1). HA=2
(2) This has a higher degree on the denominator (butt) so it is a big honking zero. HA=0
(3) This has a larger degree on top (b00bie) so it has no asymptote. Again it's silly but I think if the "b00bies" are too big they are gonna fall over and isn't going to work. HA=DNE

For yours you have the degree x/x which are the same so the leading coefficiant (numbers in front of variable) equals 1. HA=1

Holes are points on the equation that are undefined. Yours doesn't have one but on a problem like:
[(x+3)(x-3)]/(x-3) you can cross out the (x-3) on top and bottom which makes a hole. What ever you take out, solve for x when equal to 0:
x-3=0
x=3
Hole at x=3

I know it is wordy but I hope this helps!

Def is a scalene triangle