1. a boat is 15 ft away from a point perpendicular to the shoreline. a person stands at a point down the shoreline so that a 65° angle is formed between the closest point to the boat, the person, and the boat. how far is the person from the boat? round your answer to the nearest tenth of a foot. show your work.

the discriminant is 64 + 4*1*12 = 112

this is prime.

step-by-step explanation:

hello from mrbilldoesmath!

answer:   (7x + 6y) ( 49x^2 - 42xy + 36y^2)

discussion:

in general, the factorization of a^3 + b^3 is

a^3 + b^ 3 = (a + b) ( a^2 - ab + b^2)

in our case note that 343 = 7^3 and 216 = 6^3 so the equation becomes:

343x^3 + 216y^3 = (7x)^3 + (6y)^3

if you think of a (above) as 7x and b as 6y the factorization becomes

343x^3 + 216y^3 =

((7x + 6y) (   (7x)^2 - 7x*6y + (6y)^2)   =

(7x + 6y) ( 49x^2 - 42xy + 36y^2)

you,

mrb

(a + b) (a^2 - a b + b^2)

d.) 48 units

step-by-step explanation:

the closest answer i got was 75 divided by 9 = 8.3

8 pages of sport cards 9 sports cards on each page

hope that