Asegment of a circle has a 120 arc and a chord of 8in. find the area of the segment

Step-by-step explanation:

Given a segment of a circle has a 120 arc and a chord of 8 in. We have to find the area of segment.

As, radius from the centre perpendicularly bisect the chord ∴ 120 degree arc is also bisected.  

Hence, we get a right triangle with the radius of circle the hypotenuse and 4 opposite side and the 60 degree angle i.e

In ΔOAB

AB=4 in

∠AOB=60°

⇒

Now, we have to find the area of triangle ODB

x² + 3x + 7 = 0       [ax² + bx + c]

a = 1

b = 3

c = 7

quadratic formula:

    (+/- is this ±)

plug in the numbers into the variables

your answer is a

1.30

step-by-step explanation: