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Mathematics, 18.10.2019 12:30 whitakers87

In square $abcd$, $e$ is the midpoint of $\overline{bc}$, and $f$ is the midpoint of $\overline{cd}$. let $g$ be the intersection of $\overline{ae}$ and $\overline{bf}$. prove that $dg = ab$.


In square $abcd$, $e$ is the midpoint of $\overline{bc}$, and $f$ is the midpoint of $\overline{cd}$

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