The total scores on the medical college admission test (mcat) in 2013 follow a normal distribution with mean 25.3 and standard deviation 6.5.
(a) what are the median and the fi rst and third quartiles of the mcat scores? what is the interquartile range?
(b) give the interval that contains the central 80% of the mcat scores.

In a normal distribution, the median is the same as the mean (25.3). The first quartile is the value of such that



You have



For the standard normal distribution, the first quartile is about , and by symmetry the third quartile would be . In terms of the MCAT score distribution, these values are




The interquartile range (IQR) is just the difference between the two quartiles, so the IQR is about 8.8.

The central 80% of the scores have z-scores such that



That leaves 10% on either side of this range, which means



You have



Converting to MCAT scores,




So the interval that contains the central 80% is (give or take).

Intersecting secant-tangent theorem states that if a tangent segment and a secant segment are drawn to a circle from an exterior point, then the square of the measure of the tangent segment is equal to the product of the measures of the secant segment and its external secant segment.so to break it down: 1. pq acts as the tangent and ps as the secant with an intersection at p.sr = 21rp = 3x + 3pq = 4x + 4following to equation: tangent squared = the two segments multiplied by each otherso (4x + 4) ^ 2 = (3x + 3) • (21) simplifies to 16x^2 - 31x - 47 = 0 or (16x - 47)(x + 1) x = -1 or x = 47/162. pq acts as the tangent and ps as the secant with an intersection at p (again! )sr = 16rp = xpq = 15(15) ^ 2 = 16 • x225 = 16xx = 225/163. the interesting chords are proportional to each other so a ratio is possible to set up: ap dp 10 3 + x = = —— = pc pb 8 xcross multiple to get 10x = (3 + x)(8)x = 12