Write an equation for the line perpendicular to y = 5x – 12 that contains (–3, –1).
a.
x + 1 = 5(y + 3)
c.
y + 1 = 5(x + 3)
b.
y + 1 = -1/5(x + 3)
d.
y + 3 = -1/5(x + 1)

Y = 5x - 12
Here, slope = 5
Perpendicular line slope = -1/5  [ opposite and reciprocal ]

Now, y - y1 = m(x - x1)
y + 1 = -1/5 (x + 3)

In short, Your Answer would be Option B

Hope this helps!

The answer is B

Write an equation for the line perpendicular to y = 5x – 12 
that contains (–3, –1).

The given equation has slope = 5

The desired equation must have slope = -1/5

Form: y = mx + b
Solve for "b" when m = -1/5 and y = -1 when x = -3


-1 = (-1/5)(-3) + b
-1 = (3/5) + b
b = -8/5

Answer=y + 1 = 5(x + 3)

First subtract 10 from both side
y^2+6y-16=0
(y+8)(y-2)=0
-8 and 2

Answer is a not really sure tho