Aquantity, y, varies directly as x. when y = 10, x = 6. find x when y = 14. 4.3 8.4 23.3 60

If y varies directly with x, x/y must remain the same for all valid values of x and y. So, x/y must equal 6/10 for all the values of y you posted. If y = 14, x = 8.4 because 8.4/14 = 6/10, and so on. (y = 14, x = 8.4), (y = 4.3, x = 2.58), (y = 8.4, x = 5.04), (y= 23.3, x = 13.98), and (y = 60, x = 36). Furthermore, to find a value of x for a given value of y, manipulate x/y = k to make the process even easier. What we want to do is isolate x. So, (x/y) * y = k * y, which simplifies to x = ky. Now, use it by plugging in the value of k, which is 6/10, and then plugging in the value of y that you need to find an x-value for. For example, if y = 14 it should look like this x = (6/10)(14). Now that you've done that, evaluate the equation, and you should arrive at x = 8.4.

17 is c. congruent means equal in size

There are two bc a studen that equals to 2