Ahollow ball is made of rubber that is 2 cm thick. the ball has a radius to the outside surface of 6 cm.

what is the approximate volume of rubber used to make the ball?

use 3.14 to approximate pi.

a. 33.5 cm³

b. 267.9 cm³

c. 636.4 cm³

d. 904.3 cm³

The answer is C. 636.4 cm³

Step 1. Calculate the volume of the ball with radius to the outside surface (V1 = ?).
Step 2. Calculate the volume of the ball with radius to the inside surface (V2 = ?).
Step 3. Find a difference between two volumes (V1 - V2) which is actually the approximate volume of rubber used to make the ball (V = ?)

The volume of the sphere with radius r is:
V = 4/3 * π * r³

Step 1. V1 = ?
V1 = 4/3 * π * r1³

r1 = 6 cm
π = 3.14
V1 = 4/3 * 3.14 * 6³
V1 = 4/3 * 3.14 * 216
V1 = 904.32 cm³

Step 2. V2 = ?
V2 = 4/3 * π * r2³

The radius to the inside surface is actually a difference between the radius to the outside surface (6 cm) and the thickness of the rubber (2 cm).
r2 = 6 cm - 2 cm = 4 cm
π = 3.14
V2 = 4/3 * 3.14 * 4³
V2 = 4/3 * 3.14 * 64
V2 = 267.95 cm³

Step 3. The volume of the rubber (V) is:
V = V1 - V2 = 904.32 cm³ - 267.95 cm³ = 636.37 cm³ ≈ 636.4 cm³

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