The population of deer in a forest was measured to be 1,938 in the year 2010. if the population increased by a steady rate of 4% per year, which of the following calculations would predict its population in 2013?

Hence, the population of deer in the year 2013 will be:

2180.

Step-by-step explanation:

It is given that:

The population of deer in a forest was measured to be 1,938 in the year 2010.

If the population increased by a steady rate of 4% per year.

Let P(t) denotes the population of the deer in the forest in 't' years.

This means that the population function P(t) can be defined as:

i.e. in the year 2010 let t=0.

in the year 2011 let t=1.

in the year 2012 t=2

and in the year 2013, t=3

Hence, the population of the deer in the year 2013 is given by:

which is approximately given as:

Hence, the population of deer in the year 2013 will be:

2180.

a. -0.3 > -0.33

in the math equation 8 x 7 = 56, the 8 and the 7 are both factors of 56, since in this lesson we will use square tiles to figure out the factors of a whole find as many different arrays as you can, but follow one important rule: all the rows must have the i can make two rows of nine, so 2 and 9 are both factors of 18.

step-by-step explanation: