The line with equation x−y=0 coincides with the terminal side of an angle θ in standard position in quadrant iii .

what is the value of tanθ

value of tanθ = 1

Step-by-step explanation:

Given the line of the equation: x -y = 0

We can write this as;

y = x.

In Quadrant III, value of tangent is positive i.e,

We know the equation of line is given by : y=mx+b where m is the slope of line and b is the y-intercept.

On comparing with the given equation:

m =1 , b = 0

Since, slope(m) = 1

Using Slope(m) =

therefore, the value of tanθ = 1

g = (2, 2)

step-by-step explanation:

given the ratio is 1 : 1 then f is the midpoint of eg

let the coordinates of g = (x, y)

using the midpoint formula

(0 + x) = 1 ( multiply both sides by 2 )

0 + x = 2 ⇒ x = 2

similarly

(4 + y) = 3 ( multiply both sides by 2 )

4 + y = 6 ( subtract 4 from both sides )

y = 2

coordinates of g = (2, 2)

the answer will be