Solve this quadratic equation:

3x^{2}-9x+1=0

Quadratic Equation: 3x² - 9x + 1 = 0
Compare it with, ax² + bx + c = 0

Here, a = 3, b = -9, c = 1, 
Now, d = b² - 4ac
d = (-9)² - 4(3)(1)
d = 81 - 12
d = 69

Roots = -b +- √d / 2a
So, 9 + √69 / 2 or 9 - √69 / 2

In short, Your Roots would be: (9+√69) / 2 & (9-√69)/2
[ You can also simplify it in decimal numbers by putting the value of √69 which is approx. 8.30 ]

Hope this helps!

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