The area of a rectangle is 56 cm. the length is 2 cm more than x and the width is 5 cm less than twice x. solve for x. round to the nearest whole number

x = 6

Step-by-step explanation:

Given : The area of a rectangle is 56 cm². The length is 2 cm more than x and the width is 5 cm less than twice x.

We have to find the value of x.

Given area of rectangle = 56 cm²

Length  is 2 cm more than x  mathematically written as

L = 2 + x

Width is 5 cm less than twice x  mathematically written as

W = 2x - 5

Thus, we know area of rectangle = length × width

Substitute, we  have,

56 = (2 + x)(2x - 5)

Multiply each term of first bracket with each term of second bracket , we have,

Simplify, we have,

Subtract 56 both sides, we have,

Simplify , we get,

Using quadratic formula for the general equation , we have

Simplify, we get,

Also,

We get,

Thus,

Simplify, we get,

Since, x has to be whole number so x = 6

7

step-by-step explanation:

the answer would be 7

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15