Asmall submarine starts at –1,260 feet in relation to sea level. then it descends 5 feet per minute for 12 minutes. what is the new position of the submarine in relation to sea level?

Hello!

Okay so our starting point is - 1,260 feet

Now it is descending (-) 5 ft per minute for 12 minutes

So we multiply -5 (negative because it is descending) by 12

-5 x 12 = -60

So now we add -60 to -1,260

This would be -1,320

So the submarine's new position in relation to the sea level is -1,320

Hope this helped. Have a great day!

Equation would be: -1260 - 5x
Where x = number of minutes, 

After 12 minutes, it would be:
-1260 - 5(12)
-1260 - 60
-1320

In short, Your Answer would be -1320 Feet

Hope this helps!

The density of the cube is 40