The number x (in thousands) of cat flea collars demanded each year when the price of a collar is p dollars is expressed by the function x^3+200p^2=17,500. the collars are currently selling for $4 each and the annual number of sales is 24,272. find the approximate decrease in sales of the collar if the price of each collar is raised by $2.

Sales will decrease by 10.35%

Step-by-step explanation:

Number of collars sold each year is represented by the function

x³ + 200p² = 17500

Where x = Number of collars in thousands

p = price of a collar

Since price of the collar is increased by $2, therefore each collar will cost = $6

Now from the given equation,

x³ + 200(6)² = 17500

x³ = 17500 - 7200

x³ = 10300

x = 21.758

Since the value of x is in thousands so number of collars sold will be = 21758

Earlier number of collars selling = 24272.

Decrease in sales = 24272 - 21758 = 2514

Percentage drop in sales =

= %

Sales will decrease by 10.35%

dc=6 square root of 3 and ac is 12 square root 3

c and d

step-by-step explanation:

square root of 3/2 = 18/c

cross multiply to get 18*2=√3*c

36/√3 * √3/√3 = c

c= 36*√3/3

c=12√3

answer: i think one of the answer is $150 and $300?

step-by-step explanation: