Output in units
rent expense
direct materials
1,000
6,550
5,240
2,000
6,550
9,432
3,000
10,480
9,000
4,000
10,480
12,000
5,000
10,480
15,000
6,000
10,480
18,000
7,000
10,480
21,000
8,000
10,480
24,000
9,000
13,100
38,383
10,000
13,100
45,850
11,000
13,100
shingle enterprises is considering manufacturing a new product. it projects the cost of direct materials and rent for a range of output as shown below.
output in units
rent expense
direct materials
1,000
6,550
5,240
2,000
6,550
9,432
3,000
10,480
9,000
4,000
10,480
12,000
5,000
10,480
15,000
6,000
10,480
18,000
7,000
10,480
21,000
8,000
10,480
24,000
9,000
13,100
38,383
10,000
13,100
45,850
11,000
13,100
57,640
condition gt requires numbers instead of "null" and "0"calculate the variable cost per unit within the relevant range. (round answer to 2 decimal places,
e. g. 1.25.
variable cost per unitper unit

50

step-by-step explanation:

answer: ratio of volume of cone (with 3 times the height and equal diameter) to volume of cylinder is 2 to 1. the value of π is not used.

step-by-step explanation:

radius is diameter/2 = 4.

area of circle is π r^2.

volume of cylinder is height × area of base = hπr^2 = 3(4^2) π = 48π cubic inches.

not knowing the formula for volume of cone, i calculate it using calculus (which is for calculating things).

volume of cone is integral 0 to h area(y) dy. area(y) is π r(y)^2. r(y) runs r to zero as y runs zero to h, r(0) = r, r(h) = 0.

r(y) = r - r/h y

area(y) = π (r - r/h y)^2 = π (r^2 - 2r^2y/h + r^2y^2/h^2) = π r^2(1-2y/h+y^2/h^2)

antiderivative area(y) = π r^2 (y-y^2/h+y^3/(3h^2))

integral 0 to h = π r^2(h-h^2/h+h^3/(3h^2) - (0)) = π r^2(h - h + h/3) = π r^2(h/3) = π/3 r^2 h

volume of this cone is π/3(4^2)18 cubic inches.

= 6 16 π = 96π cubic inches.

cone has twice the volume, 96/48.

cone height is 6 times the cylinder.

ratio of volume formula: π r^2 cancels.

cone over cylinder ratio is 6h/3 to h, 2 to 1.