The cost of paint used in a redecorating job is $65.70. this is a reduction from its original cost is $82.13. what is the percent decrease in the cost of paint to be nearest percent?

24

Step-by-step explanation:

To find

cost per liter, we divide the total cost by liters.

Hint #22 / 8

\phantom{=}\dfrac{~~~60 \text{ dollars}~~~}{2\dfrac12 \text{ liters}}=

2

2

1

 liters

  60 dollars  

empty space, start fraction, space, space, space, 60, start text, space, d, o, l, l, a, r, s, end text, space, space, space, divided by, 2, start fraction, 1, divided by, 2, end fraction, start text, space, l, i, t, e, r, s, end text, end fraction

Hint #33 / 8

= 60 \div 2\dfrac12 =60÷2

2

1

        equals, 60, divided by, 2, start fraction, 1, divided by, 2, end fraction,8  60 =60÷   2     5    equals, 60, divided by, start fraction, 5, divided by, 2, end fraction

55 / 8 = 60   2{5}=60 ⋅ 5/2

equals, 60, dot, start fraction, 2, divided by, 5, end fraction,

{120}{5}

5   120  equals, start fraction, 120, divided by, 5, end fraction,#77 / 8=24

The cost per liter of paint was \$24$24dollar sign, 24.

intensity of the vector is v= √37 ≈ 6.08 units and make angle ∡α ≈ 9.46° with east direction

step-by-step explanation:

required vector is consists of the two componentsvx= 2+4=6 units   and vy= 1 unit and vx ⊥ vywe will use pythagorian theorem to find intensity of the vector vv∧2 = vx∧2 + vy∧2 => v = √vx∧2 + vy∧2 = √6∧2 + 1∧2 = √36+1 = √37 ≈ 6.08 unitsthe angle ∡α between vector and east direction we wil find with tanαtanα = 1/6 => α = arc tanα = arc 1/6 => α ≈ 9.46°

hope this