13 + 2 (5c - 2) = 29

& explain how you get to the answer

13+2(5c-2)=29
(2*5c) and (2*-2)
13+10c-4=29
add 4
13+10c= 33
subtract 13
10c=20
divide by 10
c=2

So you want to start by subtracting (13) from both sides... 

1) 2(5c−2)=29−132) 2(5c−2)=163) 5c−2=16/2
4) 5c−2=85) 5c=8+26) 5c=107) c=5/108) this leaves you with C=2

So the first thing we do is to multiply the top equation by 3. the reason i want to do this is i notice there will be a 6y on both equations and can possibly add/subtract them. so we get 6y = -3x + 27. adding that and the second equation we get 6x = 27-15 which is 12. divide by 6 and we get 2. ∴ x = 2. substituting 2 into the first equation we get 2y = -2 + 9 which is 7. divide by 2 and we get 7/2. ∴ y = 7/2, x = 2.