![\bf \begin{cases} c(x)=4x-2\\\\ d(x)=x^2+5x \end{cases}\qquad thus \\\\\\ (c\circ d)(x)\implies \begin{array}{llll} c(x)=&4x-2\\\\ c[\ d(x)\ ]=&4(dx)-2\\\\ c[\ \boxed{x^2+5x}\ ]= &4(\boxed{x^2+5x})-2 \end{array}](/tpl/images/0443/2746/0d366.png)
Fc(x) = 4x – 2 and d(x) = x2 + 5x, what is (c o d)(x)?
a) 4x^3 + 18x^2 – 10x
b) x^2 + 9...
Mathematics, 05.01.2020 12:31 gracye
Fc(x) = 4x – 2 and d(x) = x2 + 5x, what is (c o d)(x)?
a) 4x^3 + 18x^2 – 10x
b) x^2 + 9x – 2
c) 16x^2 + 4x – 6
d) 4x^2 + 20x – 2
Answers: 1
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