Aline passes through the points (–5, 2) and (10, –1). which is the equation of the line?
a. y= -1/5x+1
b. y= 1/5x+3
c. y= -5x-23
d. y= 5x+27

The correct answer is A) y = -1/5x + 1

To find the equation of the line, start by finding the slope. You can do this by using the slope formula below.

m(slope) = (y2 - y1)/(x2 - x1)

m = (2 - -1)/(-5 - 10)

m = 3/-15

m = -1/5

Now that we have the slope, we can use it along with either point in point-slope form to get the equation.

y - y1 = m(x - x1)

y - 2 = -1/5(x + 5)

y - 2 = -1/5x - 1

y = -1/5x + 1

the answer is y < -3 or   y > 3

-3y > 7 + 2

-3 y > 9

y < -3

0.02

step-by-step explanation:

time of 9 192 631 770 periods of the radiation corresponding to the transition between the 2 hyperfine levels of the ground state of the caesium 133 atom at 0 k (but other seconds are sometimes used in astronomy)