Y=×^2+4x+1 and y=x+1
solve a linear/quadratic system by graphing and substitution.

Graphing is used when you have paper

I will not graph this equation because it takes time, sorry

but I will solve

subsitute y=x^2+4x+1
subsitute x+1 for y
x+1=x^2+4x+1
subtract x from bot sides
1=x^2+3x+1
subtract 1 from both sides
0=x^2+3x
factor
0=(x)(x+3)
if xy=0 then assume that x and y=0
so
set them to zero
x=0

x+3=0
subtract 3 from both sides
x=-3

subsitue
y=x+1
y=0+1
y=1

y=-3+1
y=-2

so the answers could be
(x,y)
(-3,-2)
(0,1)