Anya found the slope of the line that passes through the points (–7, 4) and (2, –3). her work is shown below. let (x2, y2) be (–7, 4) and (x1, y1) be (2, –3). m = = = the slope is .

the quotient is 4x^2 - 27x + 167 with a remainder of -996

step-by-step explanation:

in synthetic division, use -6 as the divisor and use the coefficients {4, -3, 5, 6}:

-6     )   4     -3     5     6

                -24   162 -1002

          4   -27   167   -996

thus, the quotient is 4x^2 - 27x + 167 with a remainder of -996.

note:   your "4x°-3x+5x+6" is ambiguous / incomplete.   i had to assume that you meant '4x^3 - 3x^2 + 5x + 6."

translate k to n and reflect across the line containing jk.