what are the zeros of the function? f(x)=x2+17x+72

In order to find zeroes of a function, we will probably want to use our quadratic formula.

-b±√b^2-4(a)(c)/2a 

If we know our values, we can plug it in. 

Our values:

A=1 (Since there is no number in front of x, it is an assumed 1)
B=17
C=72

Now, We can plug it into our formula.

BE SURE TO PUT PARENTHESIS AROUND ALL TERMS!

-(17)±√(17)^2-4(1)(72)/2(1)

Now we can type it into a calculator! 

When we plug it into the formula. It gives us two real solutions (or zeroes) which are represented as:

-8 & -9.

Answer is a not really sure tho