Amy has a box containing 6 white, 4 red, and 8 black marbles. she picks a marble randomly. it is red. the second time, she picks a white marble. in the third attempt, amy picks a white marble again. amy has not replaced the marbles she picked.
the probability that the fourth marble amy picks is black is . if amy picks a black marble in the fourth attempt, the probability that in the fifth attempt she will pick a red or a black marble is .

The probability that the fourth marble Amy picks is black

The probability that in the fifth attempt she will pick a red or a black marble P(R∩B) =

Step-by-step explanation:

To find  the probability that in the fifth attempt she will pick a red or a black marble P(R∩B) .

The total marble in beginning=6+4+8=18

After 3 attempts, the total  marbles left=18-3=15

The number of black marbles =8

The probability that the fourth marble Amy picks is black

As four marble has already picked up, then the total marbles left in the box

=18-4=14

Now, as a red marble is already picked in 1st attempt , the number of red marbles in the box now= 4-1=3

And a black marble is already picked in fourth attempt , the number of black marbles in the box now= 8-1=7

Now P(R∩B)=P(R)+P(B)=

(d)

step-by-step explanation:

given: the line in the graph passes through points (5,30) and (6,26).

then, the equation of line is:

now, put y=a(n) and x=n,

hence, option d is correct.

answer: i'm great at algebra

~coco

step-by-step explanation: