Ahelicopter is flying from hong kong to jakarta. the latitude of jakarta is -6.20°, and its longitude is 106.80°. the latitude of hong kong is 22.27°, and its longitude is 114.15°. what is the helicopter’s net change in latitude and longitude as it travels from hong kong to jakarta?

a-28.47° latitude and 7.35° longitude
b-28.47° latitude and -7.35° longitude
c28.47° latitude and -7.35° longitude
d38.34° latitude and 220.95° longitude
e-38.34° latitude and 220.95° longitude

Option A - 28.47° latitude and 7.35° longitude      

Step-by-step explanation:  

Given : A helicopter is flying from Hong Kong to Jakarta. The latitude of Jakarta is -6.20°, and its longitude is 106.80°. The latitude of Hong Kong is 22.27°, and its longitude is 114.15°.

To find : What is the helicopter’s net change in latitude and longitude as it travels from Hong Kong to Jakarta?    

Solution :

The latitude of Jakarta is -6.20°, and its longitude is 106.80°.

The latitude of Hong Kong is 22.27°, and its longitude is 114.15°.

The net change in latitude as it travels from Hong Kong to Jakarta is given by subtracting the latitude from Hong Kong to Jakarta.

i.e.

The net change in longitude as it travels from Hong Kong to Jakarta is given by subtracting the  longitude from Hong Kong to Jakarta.

i.e.

Therefore, The net change from Hong Kong to Jakarta is 28.47° latitude and 7.35° longitude.

So, Option A is correct.

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204

well what did you do it matters what you did : )

step-by-step explanation: