Least common multiple of 2,7, and 13

To work out the LCM, we need their prime factors. So:

2 is simple 2 x 1.

7 is also 7 x 1.

13 is also 13 and 1.

They all have in common "1" - so we keep that aside as 1 figure, rather than 3.

We still have the 2, 7 and 13 leftover.

We then multiply the 1 with the other figures.

So 1 x 2 x 7 x 13 is our answer.

Which is = 182.

Hope I helped:)

~FabSafxo

answ9x x 3=

step-by-step explanation:

the rocket cannot penetrate the ground, in a contextual sense, therefore the roots of this equation should be the domain of this function. i'll let you find the roots of this quadratic equation (hint: use the quadratic formula:  

1- c

2-a

step-by-step explanation:

mark brainliest!