In basketball, hang time is the time that both of your feet are off the ground during a jump.

the equation for hang time is t=2(2h/32)^1/2, where t is the time in seconds, and h is the height of the jump, in feet.

player #1 had a hang time of 0.9s. player #2 had a hang time of 0.8s. to the nearest inch, how much higher did player #1 jump than player #2?

The difference in jump of both players can be calculated by solving the given equation for .

The player-1 jump 8.00 inch higher than the player-2.

Given:

The hang time equation is

Player 1 hang time is .

Player 2 hang time is .

Consider the given equation.

Now, solve for the .

Calculate the height for Player 1.

Calculate the height for Player 2.

Calculate the difference in jump of both players,

Thus, the player-1 jump 8.00 inch higher than the player-2.

Learn more about height here:

link

341

step-by-step explanation:

all you have to do is 9x31 (which equals 279) and then 20x31 (which equals 620). then you have to subtract. 620-279=341.