One pipe can fill a tank in 36 minutes, a second can fill it in 9 minutes, and a third can fill it in 12 minutes. if the tank is empty, how long will the three pipes, operating together, take to fill it?

4 1/2 minutes

Step-by-step explanation:

This is a classic work problem.  These are solved by finding out how much of the work being done can get done in a single unit of time.  In our case minutes.

If pipe 1 takes 36 minutes to fill the tank, then it can get 1/36 of the job done in a single minute.

If pipe 2 takes 9 minutes to fill the tank, then it can get 1/9 of the job done in a single minute.

If pipe 3 takes 12 minutes to fill the tank, then it can get 1/12 of the job done in a single minute.

The sum of all of these together will take x minutes. Our equation then is this:

We need to find the LCD of those numbers and multiply through by that LCD to get rid of the fractions, cuz who likes fractions?!  The LCD is 36x; each denominator, including the x, goes into 36x evenly and that's the lowest number that each goes into evenly.  Multiplying through by the LCD:

Reducing gives us the equation:

x + 4x + 3x = 36 and

8x = 36 so

x = 4.5 minutes or 4 1/2 minutes

i believe the answer is d.

hope it you! : d

a) one student is chosen from classroom a, then a student is chosen from classroom b.  

step-by-step explanation:

independent events are ones in which the probability of one event does not affect the probability of the second event.

one student is chosen from classroom a; this does not affect the chances of choosing a student from classroom b.   this makes these independent events.

when one card is chosen from a standard deck and then set aside before a second card is chosen, the probability of the second card being chosen changes.   this makes them dependent events.

when one student is chosen from classroom a and then a second student is chosen from classroom a, the probability of choosing the second student changes.   this makes them dependent events.

when a letter is chosen from the alphabet and then a second letter is chosen, the probability of choosing the second letter changes.   this makes them dependent events.