What is the probability that a point chosen at random in the given figure will be inside the larger circle and outside the smaller circle?
enter your answer, as a fraction in simplest form, in the box.

P( that a point chosen at random in the given figure will be inside the larger circle and outside the smaller circle)= 40/49

Step-by-step explanation:

we have to find the probability  that a point chosen at random in the given figure will be inside the larger circle and outside the smaller circle.

Area of the whole figure= area of larger circle

                                        = π×14×14 cm²

                                        = 196π cm²

Area of the region inside the larger circle and outside the smaller circle

= area of larger circle- area of smaller circle

= π×14×14-π×6×6

= 160π  cm²

P( that a point chosen at random in the given figure will be inside the larger circle and outside the smaller circle)

= area of the favorable region/area of whole figure

= 160π/196π

= 40/49

the answer is 62.8 cubic units