What is the gcf of the first two terms of the polynomial 4y3+ 8y2+ 5y + 10? a 4y3 b 4 c 4y d 4y2

Hey!

Hope this helps...

You want to find what EVERY factor's common multiples are...

In this case both 4y^3 and 8y^2 have a common variable factor of y^2

Now, you want to find what the constants in front of the variable's GCF is,

In this case both 4y^3 and 8y^2 have a common constant variable of 4

So in this the Answer is D. 4y^2

step-by-step explanation:

always plug in x. in this case, x equals 4.

i'm going to first solve 4(2+3x)

1) 4(2+3(4)) use pemdas to solve.

i'm going to multiply whats in the parenthesis first, so 3 times 4=12.

2)4 (2+12) i'm then going to multiply 4 by both numbers in the parenthesis (because multiplying comes before adding)

4 times 2= 8.   4 times 12= 48

4) (8+48)= 56 (answer)

i'm then going to solve 8+12x and plug in 4 for x.

1) 8 +12(4)

multiplying comes before adding, so i'm gonna multiply 12 and 4.

12 times 4= 48.

2) 8+48=56

both equal the same!

idk

step-by-step explanation:

use that smart brain