Mathematics, 02.02.2020 18:43 Kidmarkham4475
Find all solutions in the interval [0,2pi) of the equation: 2cos(4x)-1=0
Answers: 1
![\bf 2cos(4x)-1=0\implies 2cos(4x)=1\implies cos(4x)=\cfrac{1}{2} \\\\\\ cos^{-1}\left[ cos(4x) \right]=cos^{-1}\left[ \cfrac{1}{2} \right]\implies 4x=cos^{-1}\left( \cfrac{1}{2} \right) \\\\\\ \measuredangle x = \cfrac{cos^{-1}\left( \frac{1}{2} \right)}{4}](/tpl/images/0493/5595/4d6d2.png)
is one, thus x = 
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Find all solutions in the interval [0,2pi) of the equation: 2cos(4x)-1=0...
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