Find the illegal values of b in the fraction 2b^2+3b-10/b^2-2b-8
a. b = -5 and 2
b. b =...
Mathematics, 16.09.2019 10:50 kjdog03
Find the illegal values of b in the fraction 2b^2+3b-10/b^2-2b-8
a. b = -5 and 2
b. b = -2 and 4
c. b = -2 and -4
d. b = -5, -2, 2, and 4
Answers: 2
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