What is the area of this figure?

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m²

Area of figure is 532 m²

Step-by-step explanation:

Consider the figure, It consist of a square ABCD , and two right triangles CDE and DEF.

We have to find the area of the figure

Area of figure = area of square ABCD + area of two right triangles CDE and DEF.

We find the areas separately and then add them,

First area of square ABCD,

Area of square = side × side

Given the side of square = 18 m

Area of square ABCD = 18 × 18 = 324 m²

Area of right angled triangle =

For ΔCDE , base = 18 m and height is 16 m

Area of right angled triangle CDE =

Area of right angled triangle CDE = 144 m².

Similarly, For ΔEDF , base = 8 m and height is 16 m

Area of right angled triangle EDF =

Area of right angled triangle EDF = 64 m².

Thus, Area of figure is 324 + 144 + 64 = 532 m²

y = 3x+4

step-by-step explanation:

to find the slope

slope = (y2-y1)/ (x2-x1)

    = (-8-4)/ (-4-0)

    = -12/-4

  = 3

using the slope intercept form of a line

y= mx+b

we know the slope is 3

we know the y intercept is 4 ( the point where it crosses the y axis or x=0)

y = 3x+4