Find the width and length of a rectangle with a perimeter of 108 and a width that is twice its length.

if you explain the the question more correctly i might be able to answer this better

step-by-step explanation:

check above link.

graphically?   well, you graph them both, the solutions is where they both intersect each other, since there are two solutions, meaning they will meet twice, or namely the linear will run into the quadratic curve twice, and where they meet, those x,y coordinates are the solutions to the system.