If you have a concession stand of water for $1.50 per bottle and a concession stand with sports drinks for $2.50 per bottle, how many bottles of each drink would you need to sell to collect $100?

$1.50  would need to multiply it twice and u get 3.00, so you multiply 3x34 and get $102 not exactly 100$ and sports drink is $2.50 x 2 =$5x20=100, 34 for water and 20 for sports drink to sell at least $100  of each.

I did a trial and error method: 30 (1.50)= $45 so I know that 60 bottles would be $90. To get the other $10, I multiplied 1.50  by 6 to get $9. So you would need to sell at least 70 bottles to get $100. You would have $0.50 over $100.
I did the same process for the sports drinks.
$2.50(30)= $75. I now know I need to figure out how many more I need to get the other $25. So I multiplied $2.50 by 10=$25. I know that I need to sell 40 bottles of sports drinks to sell at least $100.
Final answers: 40 bottles of sports drinks and 70 bottles of water.