What is the equation of the quadratic graph with a focus of (2, − 2) and a directrix of y = 0?

F=(h,k+p) = (2,-2)
then           h = 2
and           -2= k + p
Directrix = 0 = k - p

Solve these 2 equations and 2 unknowns yields k=-1 and p=-1
The equation is therefore,
y=(1/4p)(x - 2)^2 -1

The answer to your question is the last one