The graph of which function will have a maximum and a y-intercept of 4?
a. f(x) = 4x2 + 6x – 1
b. f(x) = –4x2 + 8x + 5
c. f(x) = –x2 + 2x + 4
d. f(x) = x2 + 4x – 4

The quadratic equation have the coefficient of less than zero therefore its graph has a maximum point and it also have y-intercept equal to 4.

The quadratic equation that have the coefficient of less than zero, then the graph of that quadratic equation have a maximum point.

Therefore according to the given equation the quadratic equation that have a maximum point are: .

Now, to evaluate the value of y-intercept, put the value of x equal to zero.

a).

put x = 0 in above equation to get the y-intercept:

So, the equation   has y-intercept -1.

b).

put x = 0 in above equation to get the y-intercept:

So, the equation   has y-intercept 5.

c).

put x = 0 in above equation to get the y-intercept:

So, the equation    has y-intercept 4.

d).

put x = 0 in above equation to get the y-intercept:

So, the equation   has y-intercept -4.

Therefore, the correct option is c).

For more information, refer the link given below:

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step-by-step explanation:

since we know that the two functions are equal, f (x) = g

(x), therefore when we equate the two equations the result should be similar to

3x = x – 4:

a. f(x) = 3x, g(x) = x – 4

equating the two functions:

3x = x – 4             (correct)

so we now got our answer (a)