Trisha had the following seven distances (in feet) in the triple jump. 29, 30, 28, 32, 28, 31, 27 what was the range of her distances?

5

Step-by-step explanation:

We know that the range to a data set is the difference between the maximum data value and the minimum data value .

The given data set :  29, 30, 28, 32, 28, 31, 27

Maximum value = 32

Minimum value = 27

Then , the range the given data set would be :-

Hence, the range of her distances = 5

hello from mrbilldoesmath!

answer:

(7 x + 6 y) (49 x^2 - 42 x y + 36 y^2)

discussion:

the trick is to recognize that 343 = 7^3 and 216 = 6^3 and, in general,

a^3 + b^3 =   (a + b) (a^2 - a b + b^2).

in our case

343x^3+216y^3   =   (7x)^3 + (6y)^3

so take a = 7x and b = 6y in the above equation to get the answer.

you,

mrb

3 qrs + 3/2 xy hope this : /

step-by-step explanation: