The piano measures 19/4 feet long does it fit in a 5 foot long space?

Piano fits in the given space.

Step-by-step explanation:

Given: Length of Piano =

           Length of Space 5 foot

To find: If piano fits in the space or not

Piano fits in the space if its length is less than length of space .i.e., 5 foot

length of piano = feet

feet is just plural of foot

So, conversion of unit not needed

Length of piano is improper fraction ( fraction whose numerator is gretaer than denominator ) So, it ca be expressed in mixed fraction.

This shows that Piano's length is more than 4 but less than 5.

Therefore, Piano fits in the given space.

the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

step-by-step explanation:

7.9m and 4.3°

step-by-step explanation:

let east be +x and north be +y, x = distance * cos θ, y = distance * sin θ  

for 3.5 south, y = -3.5  

for 8.2, x = 8.2 * cos 30 and y = 8.2 * sin 30  

for 15 west, x = -15  

total x = 8.2 * cos 30 – 15 ≈ -7.9  

total y = -3.5 + 8.2 * sin 30 = 0.6  

magnitude = [(8.2 * cos 30 – 15)^2 + 0.6^2)]^0.5  

the magnitude is approximately 7.9 m  

tan θ = y/x = 0.6/-7.9  

the angle is approximately 4.3˚ north of west