Arectangle has vertices at these coordinates.

(2, 2), (2, 5), (6, 5)

what are the coordinates of the fourth vertex of the rectangle?

enter the coordinates in the boxes.

The coordinates of the fourth vertex of the rectangle is:

(6,2)

Step-by-step explanation:

We are given three vertices of a rectangle as:

(2,2) , (2,5) , (6,5)

Now, we need to find the fourth vertex of the rectangle.

We find the fourth vertex with the help of the graph.

Clearly after plotting the three points  on the coordinate plane we observe that the fourth vertex of the rectangle is:

(6,2).

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15