Which of the following represents the zeros of f(x) = x3 − 3x2 − 2x + 6?
a.) −3, −√2, −√2
b.) 3, −√2, −√2
c.) −3, √2, √2
d.) 3, √2, −√2

D.) 3, √2, −√2

Step-by-step explanation:

Given polynomial:

Let's check all the given options, by substituting given value on x.

A.) −3, −√2, −√2

⇒ -3 is not a zero of given polynomial.

Thus, this not the required answer.

B.) 3, −√2, −√2

But by Descartes rule of sigs , f(x) have 2 positive and 1 negative root.

Thus, this is not the right answer.

C.) −3, √2, √2

-3 is not a zero of given polynomial.

Thus, this not the required answer.

D.) 3, √2, −√2

Thus, this is the right option to have zeroes of f(x).

answer: a) (0,0), (1,1), (2,8), and (3,27).

step-by-step explanation:

0^3=0

1^3=1

2^3=8

3^3=27

in effect, the exponential equation for this would me y=3^x. each x-coordinate cubed is giving the y coordinate, so a is your answer : )

i think it might be a but you might want a second opinion