For questions 1 and 2, use integer values of from –3 to 3 to graph the equation.
1) y = –2x2 + 3

1) y=-2x²+3 Therefore making a parabola
x   -3    -2   -1   0   1   2   3
y   -15  -5   1    3   1   5   15

2)y=1/3|x|-2
x   -3   -2   -1        0     1          2       3
y   -1   -1.3 -1.6    -2   -1.6    -1.3     -1