Find an equation for the line perpendicular to the line -8x+4=3 having the same y-intercept as -7x+3y=-8.

3X-4Y=12
-4Y=-3X+12
Y=-3X/-4+12/-4
Y=3X/4-3 THUS THE SLOPE OF THIS LINE IS 3/4. 
THUS A PERPENDICULAR LINE HAS A SLOPE THAT IS A NEGATIVE RECIPRICAL OF 3/4 WHICH IS -4/3
NOW FIND THE X INTERCEPT FOR 
4X-13=3Y
3Y=4X-13

Y=4X/3-13/3 TO FIND THE X INTERCEPT OF THIS LINE WE SET Y=0 THUS:
0=4X/3-13/3
4X/3=13/3
X=13/3*3/4
X=13/4 NOW WE NEED TO FIND THE Y INTERCEPT (b)
0=-4/3*13/4+b
0=-13/3+b
b=13/3 THUS THE EQUATION IS
Y=-4X/3+13/3

Best answer that i found on yahoo ok   set :   x= length of 2nd piece in cm  x- 3= length of 1st piece in cm  x-4= length of 3rd piece in cm  then since you know they all came from the 20 cm ribbon you add them together and set them equal to 20x+ x-3 +x-4 = 20  3x - 7= 20  3x= 27  x= 9  the shortest piece is the third piece which is x- 4  x-4  9-4 = 5  the length of the smallest piece is 5 cm.  the other lengths are  9 cm  6 cm