Find the 14th term of the geometric sequence 3,6,12,24.

An=a1(r)^(n-1)
a1=first term
r=common rati

common ratio is a term divded by previous term
6/3=2
r=2

first term is 3

an=3(2)^(n-1)
14th term
a14=3(2)^(14-1)
a14=3(2)^13
a14=3(8192)
a14=24576

the 14th term is 24576

The question is kind of confusing. if it's asking how many variations of answers can you give. then do 4^5 for your answer.this would be something like the first question could be a and the 2nd c or first b next c etc. if you can, ask the teacher for a better confirmation of what it's asking. if i'm assuming correctly what it's asking, it's 625 different variations.