2. the length of a rectangular floor is 4 ft longer than its width w. the area of the floor is 525 ft2. (a) write a quadratic equation in terms of w that represents the situation. (b) what are the dimensions of the floor? show your work.

The area of a rectangle is calculated by multiplying the dimensions (length and width). if we let the width be w, the length, which is 4 ft longer than the width will be represented as w+4.

(a) the quadratic equation that would best represent the given is,
                  (w)(w + 4) = 525
                                w² + 4w = 525 or w² + 4w - 525 = 0
(b) solving for the values of w in the quadratic equation,
                                  w = 21 and w = -25
thus, we take w as 21 and w+4 = 25. the dimensions of the floor are therefore 21ft and 25 ft. 
                                         

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