Amembership committee of three is formed from four eligible members. let the eligible members be represented by a, b, c, and d. the possible outcomes include s = {abc, abd, acd, bcd}.
which statements about the situation are true? check all that apply.

there are four ways to choose the committee.
there are three ways to form the committee if person d must be on it.
if seven members are eligible next year, then there will be fewer combinations.
if persons b and c must be on the committee, there are two ways to form the committee.
if persons a and c must be on the committee, then there is only one way to form the committee.

From the given sample space of S = {ABC, ABD, ACD, BCD}, it can be concluded that;

(1) There are four ways to choose the committee.
(2) There are three ways in which person D is included.
(3) If persons B and C must be included, there are two ways to form the committee.

First, think of what you know. you know that the number t the end of the equation will need to be subtracted because it is the money he lost from buying the lawn mower. and your first two weeks have negative profit, so that tells you that c and d are wrong. now you can plug any of the weeks into a and b to see which one works. i'll start with plugging week 1 into a.this isn't right because it says your answer for week one should be -90.so now we need to try the same thing with b.this one got you the right answer, (sometimes if you only check with one of the weeks multiple will work so you need to check with more of the weeks, but it worked out fine here)this means that b is the correct answer.let me know if you need more clarification. i hope this : )